#include <string>
#include <vector>
using namespace std;
long long solution(int n) {
vector<long long> pd(2000);
pd[0] = 1; pd[1] = 2;
for (int i = 2; i < n; i++)
pd[i] = (pd[i - 1] + pd[i - 2]) % 1234567;
return pd[n-1];
}
조합으로 풀었을때 시간초과 코드
void Combination(int n, int r, int index, int depth, int& res)
{
if (r == 0)
{
res++;
}
else if (depth == n)
{
return;
}
else
{
Combination(n, r - 1, index + 1, depth + 1,res);
Combination(n, r, index, depth + 1,res);
}
}
long long solution(int n) {
long long answer = 0;
int ndiv2 = n / 2;
for (int i = 0; i <= ndiv2; i++)
{
int x = 0;
Combination(n - i, i, 0, 0, x);
answer += x;
}
return answer % 1234567;
}
#include <iostream>
using namespace std;
void m_fx(int a, int b, int& answer)
{
answer++;
if (a % 2 == 1 && b - a == 1) return;
m_fx((a+1)/2, (b+1)/2, answer);
}
int solution(int n, int a, int b)
{
int answer = 0;
if (a > b) { m_fx(b, a, answer); }
else{ m_fx(a, b, answer); }
return answer;
}
다른사람의 답
int solution(int n, int a, int b)
{
int answer = 0;
while (a != b) {
a = (a + 1) >> 1; // 2 1 1
b = (b + 1) >> 1; // 4 2 1
++answer;
}
return answer;
}